Question

58.5 g of NaCl and 180 g of glucose were separately dissolved in 1000 mL of water. Identify the correct statement regarding the elevation of boiling point of the resulting solution.

• A. NaCl solution will show higher elevation of boiling point.
• B. Glucose solution will show higher elevation of boiling point.
• C. Both solutions will show equal elevation of boiling point.
• D. None will show boiling point elevation.

Hint:

Ionic compounds like NaCl dissociate in water, increasing the effect on colligative properties.

Answer 1

The Correct Option is A

Step 1: Calculating Moles of Solute
\[ {Moles of NaCl} = \frac{58.5}{58.5} = 1 { mol} \] \[ {Moles of Glucose} = \frac{180}{180} = 1 { mol} \] Step 2: Dissociation of NaCl
NaCl dissociates into two ions (\( Na^+ \) and \( Cl^- \)), increasing the effective particle concentration. Glucose does not dissociate, so the number of particles remains the same. Thus, NaCl solution will have a higher elevation in boiling point. Thus, the correct answer is (A).