Now substituting y = (6/5)z into x = (4/3)y, we get:
x = (4/3) * (6/5)z = (24/15)z = (8/5)z
The total amount to be distributed is:
P + Q + R + S = 2x + 3x + 5y + 7z = 5x + 5y + 7z
Now using the relationships found:
5x = 5((8/5)z) = 8z
5y = 6z
Substituting:
P + Q + R + S = 8z + 6z + 6z + 7z = 27z
We have:
27z = 4200
Solving for z, we get:
z = 4200/27 = 155.56
Now find P's share:
P = 2x = 2((8/5)z) = (16/5)z
P = (16/5)*155.56 ≈ 640
Thus, the share of ‘P’ is ₹640.
A shopkeeper sells an item at a 20 % discount on the marked price and still makes a 25 % profit. If the marked price is 500 rupees, what is the cost price of the item?