Question

3A → 2B,rate of reaction +d[B]/dt is equals to 

• A. – \(\frac{3}{2}\frac{d[A]}{dt}\)
• B. – \(\frac{2}{3}\frac{d[A]}{dt}\)
• C. \(-\frac{1}{3}\frac{d[A]}{dt}\)
• D. \(2d\frac{d[A]}{dt}\)

Answer 1

The Correct Option is B

The correct option is (B) : \(\frac{2}{3}\frac{d[A]}{dt}\) 

3A→2B For the given reaction we can write rate of reaction: −\(\frac{1}{3}\)=\(\frac{d[A]}{dt}\) ​=−\(\frac{1}{20}\)\(\frac{d[B]}{dt}\) ​⇒+\(\frac{d[B]}{dt}\)= −\(\frac{2}{3}\frac{d[A]}{dt}\)