Question

2CrO$_4^{2-}$ + 3SnO$_2^{2-}$ + H$_2$O → 2CrO$_2^{-}$ + 3SnO$_3^{2-}$ + 2OH$^{-}$
How many moles of OH$^{-}$ form when 50.0 mL of 0.100 M CrO$_4^{2-}$ is added to a flask containing 50.0 mL of 0.100 M SnO$_2^{2-}$?

• A. 0.100 mol
• B. 6.66 × 10$^{-3}$ mol
• C. 3.33 × 10$^{-3}$ mol
• D. 5.00 × 10$^{-3}$ mol

Hint:

Use the stoichiometry of the reaction to relate the amounts of reactants to the amounts of products.

Answer 1

The Correct Option is C

To determine the moles of OH$^{-}$, we use the stoichiometry of the reaction, where 1 mole of CrO$_4^{2-}$ reacts with 3 moles of SnO$_2^{2-}$ to form OH$^{-}$.