Question:
\(2\tan^{-1} \frac12+\tan^{-1}\frac 17=\tan^{-1}x\), then the value of \(x\) is:
\(2\tan^{-1} \frac12+\tan^{-1}\frac 17=\tan^{-1}x\), then the value of \(x\) is:
Updated On: May 21, 2024
- \(\frac {31}{17}\)
- \(\frac {17}{31}\)
- \(\frac {4}{3}\)
- \(\frac {3}{4}\)
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The Correct Option is A
Solution and Explanation
The correct option is (A): \(\frac {31}{17}\)
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