a. A total of 250 patients were treated with type A medicine and a total of 210 patients were treated with type C medicine.
b. 25 patients were treated with type A medicine only. 20 patients were treated with type C medicine only. 10 patients were treated with type D medicine only.
c. 35 patients were treated with type A and type D medicines only. 20 patients were treated with type A and type B medicines only. 30 patients were treated with type A and type C medicines only. 20 patients were treated with type C and type D medicines only.
d. 100 patients were treated with exactly three types of medicines.
e. 40 patients were treated with medicines of types A, B and C, but not with medicines of type D. 20 patients were treated with medicines of types A, C and D, but not with medicines of type B.
f. 50 patients were given all the four types of medicines. 75 patients were treated with exactly one type of medicine.
How many patients were treated with medicine type B?
Solution and Explanation
Only 500 of the 1,000 patients have been considered for the treatment. This is our example set. This group of 500 people has thus rAlternative Texteceived the four drugs A, B, C, and D, with the remaining 500 receiving the placebo. The four-set Venn diagram that follows can be created using the information that has been provided:
We can tackle for the quantity of patients who were managed the medications A, B and D barring C by placing in the qualities for set A. 250 minus (25, 20, 30, 40, 20, 50, and 35) equals 30. In view of condition (c), we realize that 100 patients were treated with precisely three sorts of meds. In this manner, we can fill the space for the quantity of patients who were regulated just B, C and D barring A by 100 - (40+20+30) = 10. In a similar vein, we are aware, as indicated by condition (f), that the number of candidates who received only dig B is 75 - (25+20+10) = 20. 210 - (30+20+40+50+10+20+20) = 20 allows us to easily determine the number of people who received only drugs B and C. We can fill in the above values to acquire the accompanying chart
All of the values ought to add up to 500. We get x = 150 by solving for "x," which is the number of people who were only given drugs B and D. The final illustration would look like this:
Based on the above, the number of patients who were treated with medicine type B is equal to 340.
The number of patients who were treated with medicine types B, C and D, but not type A was:
Solution and Explanation
As we probably are aware there are 1000 subjects and just 500 have been considered for treatment and the remainder of 500 have been given a fake treatment. Our sample set is thus created. Subsequently the four medications A, B, C and D have been managed to this arrangement of 500 people. so based on the data given in the inquiry, we can draw the accompanying arrangement of Venn outlines.
According to the question, 250 patients received type A medication. Using this information, we can use Set A values to calculate the number of patients who received drugs A, B, and D—excluding C. 250 - (25 + 20 + 30 + 40 + 20 + 50 + 35) = 30 is the required amount. We know that exactly three different medications were used to treat 100 patients in accordance with condition (d). As a result, the number of patients who received only B, C, and D without A can be filled. The required amount is equal to 10 minus 20 minus 40. According to condition (f) 75 patients were treated with precisely one kind of medication so utilizing that we can ascertain up-and-comers who were regulated just medication B. ⇒75 - (25 +20 + 10) = 20 As a result of this, we are able to easily determine the number of patients treated solely with drugs B and C because we are aware that 210 patients received type C medication. .. The necessary worth = 210 - (30+20 + 40+ 50 + 10 + 20 + 20) = 20 We can fill in the above Venn outline to acquire following graph
According to address complete 500 patients were considered for treatment so the aggregate ought to be 500. In view of this data we can work out the worth of x which addresses the quantity of individuals who were managed drug B and D as it were ⇒x= 500 - (25 +20 +20 + 30+ 40+20 +20 +20 + 50 + 10 +20 + 35 +30 + 10) = 150
The number of patients who were treated with medicine types B, C and D, but not type A was:10
How many patients were treated with medicine types B and D only?
Solution and Explanation
Given the information provided, let's solve for the number of patients treated with medicine types B and D only.
We start by using the information given:
From condition (c), we have:
\[25 + 20 + 30 + x + 20 + 20 + y = 250\]
\[115 + x + y = 250\]
\[x + y = 250 - 115\]
\[x + y = 135\]
Now, from condition (d), 100 patients were treated with exactly three types of medicines. So, we add the number of patients treated with all four types (50) to this to get the total number of patients treated with at least three types:
\[100 + 50 = 150\]
We'll replace this value with \( x + 20 + z + y \):
\[150 = x + 20 + 50 + y\]
\[80 = x + y\]
Now, we have two equations:
\[x + y = 135\] (from condition c)
\[x + y = 80\] (from condition d)
Now, we can solve for \(x\) and \(y\):
\[135 = 80\]
\[x = 135 - 80\]
\[x = 55\]
\[y = 135 - x\]
\[y = 135 - 55\]
\[y = 80\]
Now, we can calculate the number of patients treated with medicine types B and D only:
\[ \text{B and D only} = 100 + 20 = 120 \]
But we need to subtract this from the total to get the number treated with B and D only:
\[ \text{B and D only} = 1000 - (250 + 55 + 210 + 80 + 25 + 20 + 20 + 10 + 20 + 30 + 20 + 20 + 20 + 25 + 40 + 20 + 10 + 50 + 75) \]
\[ \text{B and D only} = 1000 - 1020 = 150 \]
So, the number of patients treated with medicine types B and D only is 150.
The number of patients who were treated with medicine type D was:
Solution and Explanation
According to address complete 500 patients were considered for treatment so the aggregate ought to be 500. In view of this data we can work out the worth of x which addresses the quantity of individuals who were managed drug B and D as it were ⇒x= 500 - (25 +20 +20 + 30+ 40+20 +20 +20 + 50 + 10 +20 + 35 +30 + 10) = 150
The required value is 250 - (25 + 20 + 30 + 40 + 20 + 50 + 35) = 30. Based on condition (d), we know that 100 patients were treated with exactly three types of medicine. According to the question, 250 patients were treated with type A medicine, so we can use that to solve for the number of patients who were given drugs A, B, and D excluding C. Hence we can fill the opening for the quantity of patients who were regulated just B, C and D barring A. ..the necessary worth = 100 - (20+ 40+30) = 10 According to condition (f) 75 patients were treated with precisely one kind of medication so utilizing that we can compute up-and-comers who were controlled just medication B. The required value is 210-(30+20 + 40+ 50+ 10+ 20+ 20) = 20. We can fill in the Venn diagram above to get the diagram below. 75-(25 + 20 + 10) = 20. Following this, we can easily calculate the number of people who were given only drugs B and C because we know that 210 patients were treated with type C medicine.
According to address complete 500 patients were considered for treatment so the aggregate ought to be 500. We can determine the value of x, which represents the number of people who received only drugs B and D, using this information:
x=500 - (25 + 20 + 20 + 30 + 40 + 20 + 20 + 50 + 10 + 20 + 35 + 30 + 10)= 150
The number of patients who were treated with medicine type D was:325
Top Questions on Data Analysis
- The figure below shows a network with three parallel roads represented by horizontal lines R-A, R-B, and R-C and another three parallel roads represented by vertical lines V1, V2, and V3. The figure also shows the distance (in km) between two adjacent intersections. Six ATMs are placed at six of the nine road intersections. Each ATM has a distinct integer cash requirement (in Rs. Lakhs), and the numbers at the end of each line in the figure indicate the total cash requirements of all ATMs placed on the corresponding road. For example, the total cash requirement of the ATM(s) placed on road R-A is Rs. 22 Lakhs.
The following additional information is known.
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PAT: The firm’s profits after taxes in Rs. crores,
ES: The firm’s employee strength, that is the number of employees in the firm, and PRD: The percentage of the firm’s PAT that they spend on Research and Development (R&D).
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6. 4 and 6 are placed in the same row. - Eight gymnastics players numbered 1 through 8 underwent a training camp where they were coached by three coaches - Xena, Yuki, and Zara. Each coach trained at least two players. Yuki trained only even numbered players, while Zara trained only odd numbered players. After the camp, the coaches evaluated the players and gave integer ratings to the respective players trained by them on a scale of 1 to 7, with 1 being the lowest rating and 7 the highest.
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