Question

$^{10_{5}$B + $^{4}_{2}$He $\rightarrow$ X + $^{1}_{0}$n. In the above nuclear reaction, X will be}

• A. $^{14}_{7}$N
• B. $^{13}_{7}$N
• C. $^{12}_{6}$C
• D. $^{12}_{7}$N

Hint:

Nuclear reaction rule: \begin{itemize} \item Conserve mass number (A) \item Conserve atomic number (Z) \item Identify element using periodic table \end{itemize}

Answer 1

The Correct Option is B

Concept: In nuclear reactions: \begin{itemize} \item Mass number conserved \item Atomic number conserved \end{itemize} Step 1: Mass number balance \[ 10 + 4 = A_X + 1 \] \[ 14 = A_X + 1 \Rightarrow A_X = 13 \] Step 2: Atomic number balance \[ 5 + 2 = Z_X + 0 \] \[ 7 = Z_X \] Atomic number 7 corresponds to nitrogen (N). Conclusion: \[ X = ^{13}_{7}\text{N} \]