Question:

Find the integrals of the function: \(\frac {1}{sin \ x\  cos^3 x}\)

Updated On: Oct 4, 2023
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Solution and Explanation

\(\frac {1}{sin \ x\  cos^3 x}\)

\(\frac {sin^2x+cos^2x}{sin \ x\  cos^3 x}\)

\(\frac {sin\  x}{cos^3 x}\) + \(\frac {1}{sin \ x .\cos \ x}\)

= tan x sec2x + \(\frac {1/cos^2 x}{sin x .cos x/cos^2 x}\)

= tan x sec2x + \(\frac {sec^2 x}{tan \ x}\)

∴ \(\int\frac {1}{sin \ x\  cos^3 x}dx\) = \(∫tan \ x .sec^2 x \ dx\)\(∫\frac {sec^2 x}{tan \ x} dx\)

Let tan x = t ⇒ sec2x dx = dt
⇒ \(\int\frac {1}{sin \ x\  cos^3 x}dx\) = \(∫tdt\) + \(∫\frac 1t dt\)

\(\frac {t^2}{2 }\)\( log|t| +C\)

=\(\frac 12 tan^2 x +log|tan x|+C\)

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Concepts Used:

Methods of Integration

Given below is the list of the different methods of integration that are useful in simplifying integration problems:

Integration by Parts:

 If f(x) and g(x) are two functions and their product is to be integrated, then the formula to integrate f(x).g(x) using by parts method is:

∫f(x).g(x) dx = f(x) ∫g(x) dx − ∫(f′(x) [ ∫g(x) dx)]dx + C

Here f(x) is the first function and g(x) is the second function.

Method of Integration Using Partial Fractions:

The formula to integrate rational functions of the form f(x)/g(x) is:

∫[f(x)/g(x)]dx = ∫[p(x)/q(x)]dx + ∫[r(x)/s(x)]dx

where

f(x)/g(x) = p(x)/q(x) + r(x)/s(x) and

g(x) = q(x).s(x)

Integration by Substitution Method

Hence the formula for integration using the substitution method becomes:

∫g(f(x)) dx = ∫g(u)/h(u) du

Integration by Decomposition

Reverse Chain Rule

This method of integration is used when the integration is of the form ∫g'(f(x)) f'(x) dx. In this case, the integral is given by,

∫g'(f(x)) f'(x) dx = g(f(x)) + C

Integration Using Trigonometric Identities