Question:

1 M and 2.5 litre NaOH solution mixed with another 0.5 M and 3 litre NaOH solution. Then find out molarity of resultant solution : -

Updated On: Jun 21, 2024
  • 0.80 M
  • 1.0 M
  • 0.73 M
  • 0.50 M
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The Correct Option is C

Solution and Explanation

Moles of $2.5\, L$ of $1\, M\, NaOH$ = $2.5 \times 1 = 2.5\, Moles$ of $3.0\, L$ of $0.5\, M\, NaOH = 3.0\times 0.5 = 1.5$
Total moles of $NaOH$ in solution $=2.5+1.5=4.0$
(Total volume of solution = $2.5 + 3.0 = 5.5\, L)$
Thus $ M_1 \times V_1 = M_2\times V_2$
$ 4.0 = M_2 \times 5.5$
$\therefore$ Molarity of resultant solution = $M_2 = \frac {4.0}{5.5} M $
$\approx 0.73 \,\, M $
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Concepts Used:

Solutions

A solution is a homogeneous mixture of two or more components in which the particle size is smaller than 1 nm.

For example, salt and sugar is a good illustration of a solution. A solution can be categorized into several components.

Types of Solutions:

The solutions can be classified into three types:

  • Solid Solutions - In these solutions, the solvent is in a Solid-state.
  • Liquid Solutions- In these solutions, the solvent is in a Liquid state.
  • Gaseous Solutions - In these solutions, the solvent is in a Gaseous state.

On the basis of the amount of solute dissolved in a solvent, solutions are divided into the following types:

  1. Unsaturated Solution- A solution in which more solute can be dissolved without raising the temperature of the solution is known as an unsaturated solution.
  2. Saturated Solution- A solution in which no solute can be dissolved after reaching a certain amount of temperature is known as an unsaturated saturated solution.
  3. Supersaturated Solution- A solution that contains more solute than the maximum amount at a certain temperature is known as a supersaturated solution.