Question:
1 L, 0.02 M solution of [Co(NH3)5 SO4]Br is mixed with 1 L, 0.02 M solution of [Co(NH3)5Br]SO4. The resulting solution is divided into two equal parts (X) and treated with excess of AgNO3 solution and BaCl2 solution respectively as shown below:
1 L Solution (X) + AgNO3 solution (excess) → Y
1 L Solution (X) + BaCl2 solution (excess) → Z
The number of moles of Y and Z respectively are
1 L, 0.02 M solution of [Co(NH3)5 SO4]Br is mixed with 1 L, 0.02 M solution of [Co(NH3)5Br]SO4. The resulting solution is divided into two equal parts (X) and treated with excess of AgNO3 solution and BaCl2 solution respectively as shown below:
1 L Solution (X) + AgNO3 solution (excess) → Y
1 L Solution (X) + BaCl2 solution (excess) → Z
The number of moles of Y and Z respectively are
1 L Solution (X) + AgNO3 solution (excess) → Y
1 L Solution (X) + BaCl2 solution (excess) → Z
The number of moles of Y and Z respectively are
Updated On: Sep 14, 2024
- $0.02,0.02$
- $0.02,0.01$
- $0.01,0.01$
- $0.01,0.02$
Hide Solution
Verified By Collegedunia
The Correct Option is C
Solution and Explanation
Correct answer is (c) 0.01,0.01
Was this answer helpful?
1
0
Top Questions on Solutions
- The solution from the following with highest depression in freezing point/lowest freezing point is
- A molecule X associates in a given solvent as per the following equation:
X ⇌ (X)n
For a given concentration of X, the van’t Hoff factor was found to be 0.80 and the
fraction of associated molecules was 0.3. The correct value of ‘n’ is: - Solubility product of CaC₂O₄ at a given temperature in pure water is 4 × 10⁻⁹ mol²/L². Solubility of CaC₂O₄ at the same temperature is:
- KCET - 2024
- Chemistry
- Solutions
- The value of 'A' in the equation \( \lambda_m = \lambda_m^0 - A\sqrt{C} \) is same for the pair
- KCET - 2024
- Chemistry
- Solutions
- Which one of the following pairs will show positive deviation from Raoult's Law?
- KCET - 2024
- Chemistry
- Solutions
View More Questions
Questions Asked in JEE Main exam
- If the function \(f(x) = \frac{\sin 3x + \alpha \sin x - \beta \cos 3x}{x^3},\) \(x \in \mathbb{R} \), is continuous at \( x = 0 \), then \( f(0) \) is equal to:
- JEE Main - 2024
- Continuity and differentiability
- The coordination geometry around the manganese in decacarbonyldimanganese(0) is
- JEE Main - 2024
- coordination compounds
- Given below are two statements:
Statement (I) : The NH2 group in Aniline is ortho and para directing and a powerful activating group.
Statement (II) : Aniline does not undergo Friedel- Craft’s reaction (alkylation and acylation). In the light of the above statements
Choose the most appropriate answer from the options given below :- JEE Main - 2024
- Aromaticity & chemistry of aromatic compounds
- A rectangular loop of length 2.5 m and width 2 m is placed at 60° to a magnetic field of 4 T. The loop is removed from the field in 10 sec. The average emf induced in the loop during this time is:
- JEE Main - 2024
- Electromagnetic induction
- Two coils have mutual inductance 0.002 H. The current changes in the first coil according to the relation \( i = i_0 \sin \omega t \), where \( i_0 = 5 \, \text{A} \) and \( \omega = 50\pi \, \text{rad/s} \). The maximum value of emf in the second coil is \( \frac{\pi}{\alpha} \). The value of \( \alpha \) is ______.
- JEE Main - 2024
- Electromagnetic induction
View More Questions
Concepts Used:
Solutions
A solution is a homogeneous mixture of two or more components in which the particle size is smaller than 1 nm.
For example, salt and sugar is a good illustration of a solution. A solution can be categorized into several components.
Types of Solutions:
The solutions can be classified into three types:
- Solid Solutions - In these solutions, the solvent is in a Solid-state.
- Liquid Solutions- In these solutions, the solvent is in a Liquid state.
- Gaseous Solutions - In these solutions, the solvent is in a Gaseous state.
On the basis of the amount of solute dissolved in a solvent, solutions are divided into the following types:
- Unsaturated Solution- A solution in which more solute can be dissolved without raising the temperature of the solution is known as an unsaturated solution.
- Saturated Solution- A solution in which no solute can be dissolved after reaching a certain amount of temperature is known as an unsaturated saturated solution.
- Supersaturated Solution- A solution that contains more solute than the maximum amount at a certain temperature is known as a supersaturated solution.