1 cal =
- 1000 J
- 273.15 J
- 80 J
- 4.18 J
The Correct Option is D
Solution and Explanation
Top Questions on Units and measurement
- Given below are two statements: Statement I : In a vernier callipers, one vernier scale division is always smaller than one main scale division. Statement II : The vernier constant is given by one main scale division multiplied by the number of vernier scale divisions. In light of the above statements, choose the correct answer from the options given below.
- JEE Main - 2025
- Physics
- Units and measurement
- A tiny metallic rectangular sheet has length and breadth of 5 mm and 2.5 mm, respectively. Using a specially designed screw gauge which has pitch of 0.75 mm and 15 divisions in the circular scale, you are asked to find the area of the sheet. In this measurement, the maximum fractional error will be \( \frac{x}{100} \), where \( x \) is:
- JEE Main - 2025
- Physics
- Units and measurement
- Choose the correct statements:
(A) Weight of a substance is the amount of matter present in it.
(B) Mass is the force exerted by gravity on an object.
(C) Volume is the amount of space occupied by a substance.
(D) Temperatures below 0°C are possible in Celsius scale, but in Kelvin scale negative temperature is not possible.
(E) Precision refers to the closeness of various measurements for the same quantity. Choose the correct answer from the options given below:- JEE Main - 2025
- Chemistry
- Units and measurement
The ratio of the power of a light source \( S_1 \) to that of the light source \( S_2 \) is 2. \( S_1 \) is emitting \( 2 \times 10^{15} \) photons per second at 600 nm. If the wavelength of the source \( S_2 \) is 300 nm, then the number of photons per second emitted by \( S_2 \) is ________________ \( \times 10^{14} \).
- JEE Main - 2025
- Physics
- Units and measurement
Two light beams fall on a transparent material block at point 1 and 2 with angle \( \theta_1 \) and \( \theta_2 \), respectively, as shown in the figure. After refraction, the beams intersect at point 3 which is exactly on the interface at the other end of the block. Given: the distance between 1 and 2, \( d = \frac{4}{3} \) cm and \( \theta_1 = \theta_2 = \cos^{-1} \left( \frac{n_2}{2n_1} \right) \), where \( n_2 \) is the refractive index of the block and \( n_1 \) is the refractive index of the outside medium, then the thickness of the block is …….. cm.
- JEE Main - 2025
- Physics
- Units and measurement
Questions Asked in AP POLYCET exam
- Find the 10th term of the arithmetic progression \(5,1,-3,-7,..….\)
- AP POLYCET - 2024
- Arithmetic Progressions
- If a sin 45°= b cosec 30°, then the value of \(\frac {a^4}{b^4}\) is
- AP POLYCET - 2024
- Trigonometry
- The ratio of the sum and product of the roots of the quadratic equation \(7x^2-12x+18=0\) is
- AP POLYCET - 2024
- Quadratic Equations
- The speed of light in vacuum is c. The speed of light in a medium of refractive index \(\frac 43\) is
- AP POLYCET - 2024
- Light - Reflection and Refraction
- If the volume of a cylinder is 500 m3 and the area of its base is 25 m2, then its height (in m) is
- AP POLYCET - 2024
- Volume of Cube, Cuboid and Cylinder