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1 2 5 1 5 8 1 8 11 1 3n 1 3n 2 is equal to
Question:
\(\frac{1}{2.5}+\frac{1}{5.8}+\frac{1}{8.11}+...+\frac{1}{(3n-1)(3n+2)}\)
is equal to
SRMJEEE - 2019
SRMJEEE
Updated On:
Oct 4, 2024
\(\frac{n}{3n+2}\)
\(\frac{n}{5n+4}\)
\(\frac{n}{6n+2}\)
\(\frac{n}{6n+4}\)
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The Correct Option is
D
Solution and Explanation
The correct option is (D):
\(\frac{n}{6n+4}\)
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