Question:

$\left(\frac{1}{1-2i} + \frac{3}{1+i}\right) \left(\frac{3+4i}{2-4i}\right)$ is equal to :

Updated On: Jul 2, 2022
  • $\frac{1}{2}+\frac{9}{2}i$
  • $\frac{1}{2}-\frac{9}{2}i$
  • $\frac{1}{4}-\frac{9}{4}i$
  • $\frac{1}{4}+\frac{9}{4}i$
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The Correct Option is D

Solution and Explanation

Let $z = \left(\frac{1}{1-2i} + \frac{2}{1+i}\right) \left(\frac{3+4i}{2-4i}\right) $ $= \left[\frac{1+i+3-6i}{\left(1-2i\right)\left(1+i\right)}\right] \left[\frac{3+4i}{2-4i}\right]$ $= \left[\frac{4-5i}{3-i}\right]\left[\frac{3+4i}{2-4i}\right] = \left[\frac{32+i}{2-14i}\right]$ $= \frac{32+i}{2-14i}\times\frac{2+14i}{2+14i} = \frac{64+448i+2i-14}{4+196}$ $= \frac{50+450i}{200} = \frac{1}{4} + \frac{9}{4}i$
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Concepts Used:

Complex Numbers and Quadratic Equations

Complex Number: Any number that is formed as a+ib is called a complex number. For example: 9+3i,7+8i are complex numbers. Here i = -1. With this we can say that i² = 1. So, for every equation which does not have a real solution we can use i = -1.

Quadratic equation: A polynomial that has two roots or is of the degree 2 is called a quadratic equation. The general form of a quadratic equation is y=ax²+bx+c. Here a≠0, b and c are the real numbers.