Question:

0 .15 g of a substance dissolved in 15 g of a solvent higher by 0.216$^\circ$C than that of the pure solvent. Find out the molecular weight of the substance. $(K_b\, for\, solvent \, is\, 2.16 ^\circ C)$

Updated On: Aug 3, 2024
  • 1.01
  • 10.1
  • 100
  • 10
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The Correct Option is C

Solution and Explanation

Elevation in boiling point, $\Delta T = K _{ b } Xm _{ b }$
Here, $K _{ b }=2.16, \Delta T =.216$
$m _{ b }=\Delta T / K _{ b }=>.216 / 2.16=0.1$
Now, molality, $m_{b}=$ Moles of solute/Mass of solvent(in kg)
$0.1 =$ Moles of solute/ $0.015$
$ \Rightarrow$ Moles of solute $=0.0015$
Finally, Moles= Mass (in gm)/ Mol. Wt
$0.0015=0.15$ / Mol wt
Mol w t $=100$
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Concepts Used:

Solutions

A solution is a homogeneous mixture of two or more components in which the particle size is smaller than 1 nm.

For example, salt and sugar is a good illustration of a solution. A solution can be categorized into several components.

Types of Solutions:

The solutions can be classified into three types:

  • Solid Solutions - In these solutions, the solvent is in a Solid-state.
  • Liquid Solutions- In these solutions, the solvent is in a Liquid state.
  • Gaseous Solutions - In these solutions, the solvent is in a Gaseous state.

On the basis of the amount of solute dissolved in a solvent, solutions are divided into the following types:

  1. Unsaturated Solution- A solution in which more solute can be dissolved without raising the temperature of the solution is known as an unsaturated solution.
  2. Saturated Solution- A solution in which no solute can be dissolved after reaching a certain amount of temperature is known as an unsaturated saturated solution.
  3. Supersaturated Solution- A solution that contains more solute than the maximum amount at a certain temperature is known as a supersaturated solution.