The e.m.f. of a Daniell cell at $298\, K$ is $E _{1}$.
$Zn / SO _{4}(0.01 M ) \| CuSO _{4}(1.0 M ) / Cu$
When the concentration of $ZnSO _{4}$ is $1.0\, M$ and that of $CuSO _{4}$ is $0.01\, M$, the e.m.f. is changed to $E _{2}$. What is the relationship between $E _{1}$ and $E _{2}$ :