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List of top Physics Questions on Electric Flux Density asked in JEE Main
An electric field,
E
⃗
=
2
i
^
+
6
j
^
+
8
k
^
6
\vec{E} = \frac{2\hat{i} + 6\hat{j} + 8\hat{k}}{\sqrt{6}}
E
=
6
2
i
^
+
6
j
^
+
8
k
^
passes through the surface of
4
m
2
4 \, \text{m}^2
4
m
2
area having unit vector
n
^
=
2
i
^
+
j
^
+
k
^
6
\hat{n} = \frac{2\hat{i} + \hat{j} + \hat{k}}{\sqrt{6}}
n
^
=
6
2
i
^
+
j
^
+
k
^
. The electric flux for that surface is _________
V m
\text{V m}
V m
.
JEE Main - 2024
JEE Main
Physics
Electric Flux Density
An electric field is given by
(
6
i
^
+
5
j
^
+
3
k
^
)
N/C
(6\hat{i} + 5\hat{j} + 3\hat{k}) \, \text{N/C}
(
6
i
^
+
5
j
^
+
3
k
^
)
N/C
. The electric flux through a surface area
30
i
^
m
2
30\hat{i} \, \text{m}^2
30
i
^
m
2
lying in the YZ-plane (in SI units) is:
JEE Main - 2024
JEE Main
Physics
Electric Flux Density