(Zn + 4HNO_3 Zn(NO_3)_2 + 2H_2O + 2NO_2)
32.5 g of zinc reacts with concentrated nitric acid as given in the above equation.
(a) How many moles of zinc was required in the reaction?
(b) Find the mass of nitric acid needed to react with 32.5 g of zinc.
(c) Find the volume of nitrogen dioxide liberated in (b).
(Atomic weight: H = 1, N = 14, O = 16, Zn = 65)