Question:

What volume of carbon dioxide is produced at STP when 5 litres of propane is burnt completely according to the equation given below?
[ C_3H_8 + 5O_2 3CO_2 + 4H_2O ]

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As long as all reactants and products are gases at the same temperature and pressure, you can use the coefficients of the balanced equation directly as volume ratios!
  • 10 litres
  • 15 litres
  • 20 litres
  • 25 litres
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The Correct Option is B

Solution and Explanation

Step 1: Understanding Gay-Lussac's Law:
According to Gay-Lussac's Law of Combining Volumes, gases react in a simple whole-number ratio by volume, provided temperature and pressure remain constant.
Step 2: Analyzing the Stoichiometry:
From the balanced equation: [ underbrace1 text vol._C_3H_8 + 5 text vol. O_2 underbrace3 text vol._CO_2 + 4 text vol. H_2O ] This means 1 litre of propane produces 3 litres of carbon dioxide.
Step 3: Calculating for 5 Litres:
Volume of CO_2 = 5 text litres (propane) times 3 = 15 text litres.
Step 4: Final Answer:
The volume of CO_2 produced is 15 litres.
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