The resistance of a conductivity cell, filled with 0.1 mol L\(^{-1}\) KCl solution is 100 \(\Omega\). If the resistance of this cell is 500 \(\Omega\) on filling 0.02 mol L\(^{-1}\) KCl solution, then calculate the conductivity and molar conductivity of 0.02 mol L\(^{-1}\) KCl solution. The conductivity of 0.1 mol L\(^{-1}\) KCl solution is 1.29 S m\(^{-1}\).