Consider the following reactions:
\[
\text{NH}_2 \text{O} \xrightarrow{\text{NaNO}_2, \text{HCl}, 0-5^\circ C} [A] \xrightarrow{\text{HCl dil.}, \text{NaOH}} [B]
\]
- (i) The molecular formula of [A] is C₁₄H₁₄N₂O₂
- (ii) The molecular formula of [C] is C₁₆H₁₈N₂O₂
The total number of sp³ hybridized carbon atoms in the major product [C] formed is -----.