Question:

Kemi samagri ni enthalpy ma kyare badi badlavi aave che?

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Esterification reactions are typically exothermic, leading to large enthalpy changes.
Updated On: Jan 20, 2026
  • \(\text{C}_6\text{H}_5\text{NH}_2 + \text{OH}\)
  • \(\text{C}_6\text{H}_5\text{CH}_2\text{OH} + \text{COOH}\)
  • \(\text{CH}_3\text{OH} + \text{CH}_3\text{COCH}_3\)
  • \(\text{CH}_3\text{CH}_2\text{Cl} + \text{OH}\)
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The Correct Option is C

Solution and Explanation


Step 1: Understanding the Question.
We are asked to identify the compound that exhibits the largest change in enthalpy (\( \Delta H \)), which corresponds to the most exothermic or endothermic reaction.
Step 2: Analyzing the Options.
- (A) \(\text{C}_6\text{H}_5\text{NH}_2 + \text{OH}\) is a reaction involving amines but does not have the largest enthalpy change.
- (B) \(\text{C}_6\text{H}_5\text{CH}_2\text{OH} + \text{COOH}\) is an alcohol-acid reaction with a moderate enthalpy change.
- (C) \(\text{CH}_3\text{OH} + \text{CH}_3\text{COCH}_3\) is an esterification reaction, which typically has a large exothermic enthalpy change.
- (D) \(\text{CH}_3\text{CH}_2\text{Cl} + \text{OH}\) involves an alkyl halide substitution, but the enthalpy change is relatively smaller.
Step 3: Conclusion.
The correct answer is (C) \(\text{CH}_3\text{OH} + \text{CH}_3\text{COCH}_3\) as it is an esterification reaction with a large change in enthalpy.
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