Question

Xenon hexafluoride on partial hydrolysis produces compounds 'X' and 'Y'. Compounds 'X', 'Y' and the oxidation state of Xe are respectively:

• A. XeOF\(_4\) (+6) and XeO\(_3\) (+6)
• B. XeO\(_2\) (+4) and XeO\(_3\) (+6)
• C. XeOF\(_4\) (+6) and XeO\(_2\)F\(_2\) (+6)
• D. XeO\(_2\)F\(_2\) (+6) and XeO\(_2\) (+4)

Hint:

The oxidation states of elements in oxyfluorides can be determined by balancing the charges of the components.

Answer 1

The Correct Option is C

Step 1: Hydrolysis of Xenon Hexafluoride.
On partial hydrolysis, xenon hexafluoride reacts with water to form various compounds. The products formed are Xenon oxyfluoride and xenon dioxide fluoride.

Step 2: Oxidation states.
The oxidation state of Xenon in XeOF\(_4\) is +6, and in XeO\(_2\)F\(_2\), it is also +6.