Let's start by defining the productivity of bullocks and tractors. Let the productivity of 1 bullock be \( B \) and 1 tractor be \( T \). Since \( X \) bullocks and \( Y \) tractors together can plough the field in 8 days, their collective productivity is \( \frac{1}{8} \) of the work (the whole field) per day. Therefore, we write:
\( X \cdot B + Y \cdot T = \frac{1}{8} \)
When we halve the number of bullocks (i.e., \( \frac{X}{2} \)) and double the number of tractors (i.e., \( 2Y \)), the new scenario takes 5 days, giving us:
\( \frac{X}{2} \cdot B + 2Y \cdot T = \frac{1}{5} \)
We now have two equations to solve for \( B \) and \( T \):
1) \( X \cdot B + Y \cdot T = \frac{1}{8} \)
2) \( \frac{X}{2} \cdot B + 2Y \cdot T = \frac{1}{5} \)
Multiply equation (1) by 2:
\( 2X \cdot B + 2Y \cdot T = \frac{1}{4} \)
Substitute this into equation (2):
\( \frac{X}{2} \cdot B + 2Y \cdot T = \frac{1}{5} \)
Subtract the second equation from the scaled equation (1):
\( (2X \cdot B + 2Y \cdot T) - (\frac{X}{2} \cdot B + 2Y \cdot T) = \frac{1}{4} - \frac{1}{5} \)
Simplify the left-hand side:
\( \frac{3X}{2} \cdot B = \frac{1}{20} \)
Solving for \( B \):
\( B = \frac{1}{30X} \)
To find how many days \( X \) bullocks will take to plough the field alone, we use:
\( X \cdot B = \frac{1}{D} \)
Substitute \( B \) from above:
\( X \cdot \frac{1}{30X} = \frac{1}{D} \)
Simplifying gives:
\( \frac{1}{30} = \frac{1}{D} \)
Therefore, \( D = 30 \).
The number of days it will take for \( X \) bullocks alone to plough the field is 30.