Question:

$x$ and $y$ are defined such that $x^2 + y^2 = 0.1$ and $|x-y| = 0.2$. Find $|x| + |y|$.

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Use $(x\pm y)^2$ expansions with given sums/products to find required expressions.
Updated On: Aug 5, 2025
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The Correct Option is B

Solution and Explanation

From $(x-y)^2 = 0.04 \ \Rightarrow \ x^2 - 2xy + y^2 = 0.04$. Given $x^2 + y^2 = 0.1$, subtract: $0.1 - 2xy = 0.04 \ \Rightarrow \ 2xy = 0.06 \ \Rightarrow \ xy = 0.03$. $(x+y)^2 = x^2 + y^2 + 2xy = 0.1 + 0.06 = 0.16$. So $|x+y| = 0.4$. For $x,y$ both positive or both negative, $|x|+|y| = |x+y| = 0.4$. \[ \boxed{0.4} \]
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