(1) The reaction involves oxidation using KMnO₄ and KOH, which leads to the formation of a carboxylic acid. The product is Benzoic acid (C₆H₅COOH).
\[
\text{C}_6\text{H}_5\text{CH}_2\text{CH}_3 \xrightarrow{\text{KMnO}_4, \text{KOH}} \text{C}_6\text{H}_5\text{COOH}
\]
(2) The reaction between benzaldehyde and acetone in the presence of dilute NaOH leads to the formation of Aldol product (4-hydroxy-4-phenylpent-3-en-2-one), followed by dehydration, which forms Cinnamon aldehyde.
\[
\text{C}_6\text{H}_5\text{CHO} + \text{CH}_3\text{COCH}_3 \xrightarrow{\text{dil NaOH}} \text{C}_6\text{H}_5\text{CH}= \text{CHCOCH}_3
\]
(3) Bromination of benzoic acid in the presence of FeBr₃ leads to the formation of 2,4,6-Tribromobenzoic acid.
\[
\text{C}_6\text{H}_5\text{COOH} \xrightarrow{\text{Br}_2 / \text{FeBr}_3} \text{C}_6\text{H}_2\text{(Br)}_3\text{COOH}
\]