Question

Write the IUPAC name of the product formed in the Reimer-Tiemann reaction. 

Hint:

The Reimer-Tiemann reaction introduces an aldehyde group ortho to the hydroxyl group on the benzene ring of phenol.

Answer 1

Reimer-Tiemann Reaction 

The Reimer-Tiemann reaction is a method used for the ortho-formylation of phenols. It involves the introduction of a formyl group (-CHO) to the aromatic ring of phenol using chloroform (CHCl₃) in the presence of a strong base, typically sodium hydroxide (NaOH).

General Reaction:

The general reaction can be represented as: \[ \text{C}_6\text{H}_5\text{OH} + \text{CHCl}_3 + \text{NaOH} \rightarrow \text{2-formylphenol} + \text{by-products} \]

Product Formed:

The product of the Reimer-Tiemann reaction is 2-formylphenol, also known as ortho-hydroxybenzaldehyde.

IUPAC Name:

The IUPAC name of the product formed in the Reimer-Tiemann reaction is 2-formylphenol.

Structure of the Product:

In this reaction, the formyl group (-CHO) is added to the ortho position (adjacent to the hydroxyl group -OH) on the benzene ring.

Conclusion:

Therefore, the IUPAC name of the product formed in the Reimer-Tiemann reaction is 2-formylphenol.