The molecular structure of isoprene is given as:
\[ \text{CH}_2 = \text{C}(\text{CH}_3) - \text{CH} = \text{CH}_2 \]
The longest continuous carbon chain that includes both double bonds contains 4 carbon atoms. Hence, the parent hydrocarbon is buta-1,3-diene.
\[ \text{C}_1 = \text{CH}_2,\quad \text{C}_2 = \text{C},\quad \text{C}_3 = \text{CH},\quad \text{C}_4 = \text{CH}_2 \]
Numbering starts from the end that gives the double bonds the lowest locants. Therefore, the double bonds are at carbons 1 and 3.
\[ \text{Buta-1,3-diene} \]
A methyl group (\(\text{-CH}_3\)) is attached to the second carbon atom of the chain.
\[ \text{Substituent: } -\text{CH}_3 \text{ on C}_2 \]
Putting it all together:
\[ \textbf{2-methylbuta-1,3-diene} \]
The IUPAC name of isoprene is \[ \boxed{\text{2-methylbuta-1,3-diene}} \]
The least acidic compound, among the following is
Solve the following assignment problem for minimization :