Question

Write the electronic configuration of \(d^5\) in terms of \( t_{2g} \) and \( e_g \) in an octahedral field as: 
\( \Delta_o>P \)
 

Hint:

The relative strength of \( \Delta_o \) and \( P \) determines whether a complex is high-spin or low-spin. A larger \( \Delta_o \) favors low-spin, while a smaller \( \Delta_o \) favors high-spin.

Answer 1

- (i) \( \Delta_o>P \): When the crystal field splitting energy (\( \Delta_o \)) is greater than the pairing energy (\( P \)), the electrons will occupy the lower-energy \( t_{2g} \) orbitals first, leading to the configuration \( t_{2g}^6 e_g^0 \). This corresponds to a low-spin configuration.
- (ii) \( \Delta_o<P \): When \( \Delta_o \) is smaller than \( P \), the electrons will prefer to occupy the higher-energy \( e_g \) orbitals to minimize repulsion, leading to the configuration \( t_{2g}^4 e_g^1 \), a high-spin configuration. Explanation:
- Crystal field splitting energy and pairing energy determine whether a complex is high-spin or low-spin. A larger \( \Delta_o \) favors low-spin, while a smaller \( \Delta_o \) favors high-spin.