Write short notes on
Sthalakosh
Sthalakosh
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Solution and Explanation
Sthalakosh
Meaning:
The term Sthalakosh refers to a geographical or regional encyclopedia that provides detailed information about various places — including their history, geography, culture, and society. It documents and preserves the identity of local regions.
Content:
- History: Key events and personalities of the region.
- Geography: Topography, climate, and physical features.
- Culture: Local traditions, languages, and festivals.
- Social Life: Customs, lifestyles, and social structures.
- Economic Activities: Main industries and livelihoods.
- Important Events: Historical moments shaping the place.
Purpose:
- To preserve local history and culture.
- To provide authentic reference material for researchers and historians.
- To trace regional development over time.
Importance:
Sthalakoshas are vital for studying local history and linking it to larger historical narratives. They help in cultural preservation, academic research, and planning based on historical insights.
\[ \text{Sthalakosh = Encyclopedia of Local Geography, Culture, and History.} \]
Top Questions on History Writing and Historiography of Ancient India
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Questions Asked in Maharashtra Class X Board exam
Complete the following activity to prove that the sum of squares of diagonals of a rhombus is equal to the sum of the squares of the sides.
Given: PQRS is a rhombus. Diagonals PR and SQ intersect each other at point T.
To prove: PS\(^2\) + SR\(^2\) + QR\(^2\) + PQ\(^2\) = PR\(^2\) + QS\(^2\)
Activity: Diagonals of a rhombus bisect each other.
In \(\triangle\)PQS, PT is the median and in \(\triangle\)QRS, RT is the median.
\(\therefore\) by Apollonius theorem,
\[\begin{aligned} PQ^2 + PS^2 &= \boxed{\phantom{X}} + 2QT^2 \quad \dots \text{(I)} \\ QR^2 + SR^2 &= \boxed{\phantom{X}} + 2QT^2 \quad \dots \text{(II)} \\ \text{Adding (I) and (II),} \quad PQ^2 + PS^2 + QR^2 + SR^2 &= 2(PT^2 + \boxed{\phantom{X}}) + 4QT^2 \\ &= 2(PT^2 + \boxed{\phantom{X}}) + 4QT^2 \quad (\text{RT = PT}) \\ &= 4PT^2 + 4QT^2 \\ &= (\boxed{\phantom{X}})^2 + (2QT)^2 \\ \therefore \quad PQ^2 + PS^2 + QR^2 + SR^2 &= PR^2 + \boxed{\phantom{X}} \\ \end{aligned}\]
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- Constructions
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