Question

Write four solutions for each of the following equations: 

(i) 2x + y = 7 

(ii) πx + y = 9 

(iii) x = 4y

Answer 1

(i) 2x + y = 7 
For x = 0, 
2(0) + y = 7 
⇒ y = 7 
Therefore, (0, 7) is a solution of this equation. 
For x = 1, 2(1) + y = 7 
⇒ y = 5 
Therefore, (1, 5) is a solution of this equation. 
For x = −1, 2(−1) + y = 7 
⇒ y = 9 
Therefore, (−1, 9) is a solution of this equation. 
For x = 2, 2(2) + y = 7 
⇒ y = 3 
Therefore, (2, 3) is a solution of this equation. 
(ii) πx + y = 9 For x = 0, π(0) + y = 9 
⇒ y = 9 
Therefore, (0, 9) is a solution of this equation. 
For x = 1, π(1) + y = 9 
⇒ y = 9 − π 
Therefore, (1, 9 − π) is a solution of this equation. 
For x = 2, π(2) + y = 9 
⇒ y = 9 − 2π 
Therefore, (2, 9 −2π) is a solution of this equation. 
For x = −1, π(−1) + y = 9 y = 9 + π (−1, 9 + π) is a solution of this equation. 
(iii) x = 4y For x = 0, 0 = 4y 
⇒ y = 0 
Therefore, (0, 0) is a solution of this equation. 
For y = 1, x = 4(1) = 4 
Therefore, (4, 1) is a solution of this equation. 
For y = −1, x = 4(−1) 
⇒ x = −4
For x=2, 2=4y
⇒ \(y=\frac{2}{4}=\frac{1}{2}\)
Therefore,  \(2,\frac{1}{2}\)
Therefore, (−4, −1) is a solution of this equation. is a solution of this equation.
The provided answer is one of the various possible solutions. This question might have other solution too.