Question

Work done to move a charge of 5C from P to Q is 10J. If the potential at P is 0.5V, then the potential at Q is:

• A. \( 2 \, \text{V} \)
• B. \( 2.5 \, \text{V} \)
• C. \( 3 \, \text{V} \)
• D. \( 4 \, \text{V} \)

Hint:

Work done in moving a charge is directly related to the potential difference between the two points. Use the formula \( W = q \Delta V \) to solve for potential difference.

Answer 1

The Correct Option is B

Let $W$ be the work done to move a charge $q$ from point P to point Q. Then,
$$W = q (V_Q - V_P)$$
where $V_Q$ is the electric potential at point Q and $V_P$ is the electric potential at point P.

Given:
$q = 5$ C
$W = 10$ J
$V_P = 0.5$ V

We have:
$$10 = 5 (V_Q - 0.5)$$
Divide both sides by 5:
$$2 = V_Q - 0.5$$
Add 0.5 to both sides:
$$V_Q = 2 + 0.5 = 2.5$$
So, the potential at Q is 2.5 V.

Final Answer: The final answer is $\boxed{2.5V}$