Question

Work done during the expansion of a gas from a volume of \(4 \, \text{dm}^3\) to \(6 \, \text{dm}^3\) against a constant external pressure of 3 atm is (1 L atm = 101.32 J)

• A. \(-608 \, \text{J}\)
• B. \(-304 \, \text{J}\)
• C. \(+304 \, \text{J}\)
• D. \(-6 \, \text{J}\)

Hint:

Work done during expansion or compression of a gas is given by \(W = -P \Delta V\), where \(P\) is the pressure and \(\Delta V\) is the change in volume.

Answer 1

The Correct Option is B

The work done is given by: \[ W = -P \Delta V \] Here, \(P = 3 \, \text{atm}\), \(\Delta V = 6 - 4 = 2 \, \text{dm}^3\). Converting pressure to \( \text{J} \), we use the conversion factor \(1 \, \text{atm} = 101.32 \, \text{J/L}\). Thus, the work done is \(-304 \, \text{J}\).