Why is \( pK_a \) of ClCH2COOH lower than the \( pK_a \) of CH3COOH?
Why is \( pK_a \) of ClCH2COOH lower than the \( pK_a \) of CH3COOH?
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Solution and Explanation
Step 2: In ClCH2COOH, the –Cl group stabilizes the conjugate base by dispersing the negative charge.
Step 3: Greater stability of the conjugate base increases acidity and hence lowers the \( pK_a \) value.
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