To determine which two figures have the same area, we need to calculate the area of each figure given in the options:
- Circle with a diameter of 14 cm (Option A):
The area of a circle is given by the formula: \(A = \pi r^2\)
Here the radius \(r\) is half of the diameter, which is \(7 \text{ cm}\).
Therefore, the area is: \(A = \pi \times 7^2 = 49\pi \text{ cm}^2\) - Rectangle with length 12 cm and breadth 10 cm (Option B):
The area of a rectangle is: \(A = \text{length} \times \text{breadth}\)
Therefore, the area is: \(A = 12 \times 10 = 120 \text{ cm}^2\) - Rectangle with length 14 cm and breadth 11 cm (Option C):
The area of a rectangle is: \(A = \text{length} \times \text{breadth}\)
Therefore, the area is: \(A = 14 \times 11 = 154 \text{ cm}^2\) - Square with side 12 cm (Option D):
The area of a square is: \(A = \text{side}^2\)
Therefore, the area is: \(A = 12^2 = 144 \text{ cm}^2\)
Comparing the computed areas, we find that:
- Circle (Option A) has an area of \(49\pi \approx 153.86 \text{ cm}^2\).
- Rectangle (Option C) has an area of \(154 \text{ cm}^2\).
Since the area of Option A (approximately 153.86 cm2) is very close to the area of Option C (154 cm2), we conclude that Options A and C have the same area, considering permissible approximation differences in exams.
Therefore, the correct answer is: A and C only.