Step 1: Reconstruct without using (III).
From (II) & (VI): bottom \(=\) Red, top \(=\) Black.
From (IV) and (V): Blue must sit between White and Brown on the side ring \(\Rightarrow\) the 4 side faces are \(\{ \text{White},\ \text{Blue},\ \text{Brown},\ \text{Green} \}\); the only remaining colour is Green, which therefore is also a side face.
Step 2: Compare with (III).
(III) says "Green is between Red and Black'' — i.e., a side face touching both top and bottom.
But we already deduced that Green is on the side ring from (II), (IV), (V), (VI) alone.
Step 3: Conclude.
Thus \(\boxed{\text{(III) is redundant}}\); it adds nothing beyond the other statements.