Question:

Which order is correct in spectrochemical series of ligands:

Updated On: Apr 7, 2025
  •  Cl-<F-<H2O<[C2O4]2-<CN-

  •  Cl-<F-<CN-<H2O<[C2O4]2- 

  •  F-<Cl-<CN-<H2O<[C2O4]2- 

  •  F-<Cl-<H2O<CN-<[C2O4]2- 

  •  Cl-<F-< [C2O4]2-<H2O<CN- 

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The Correct Option is A

Approach Solution - 1

Spectrochemical Series Analysis:

Correct weak-to-strong field order: \[ \text{Cl}^- < \text{F}^- < \text{H}_2\text{O} < \text{C}_2\text{O}_4^{2-} < \text{CN}^- \]

Key features:

Halides are weak field (Cl^- weaker than F^-)

H2O is intermediate field

CN^- is strongest field ligand

Thus, the correct option is (A): \(Cl^- < F^- < H_2O < [C_2 O_4]^{2-} < CN^-\).

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Approach Solution -2

1. Understanding the spectrochemical series:

The spectrochemical series is an arrangement of ligands based on their ability to cause crystal field splitting (\( \Delta \)) in a metal complex. Ligands that cause a larger splitting are called strong-field ligands, while those causing smaller splitting are weak-field ligands.

2. General order of common ligands in the spectrochemical series:

  • Weak-field ligands (small \( \Delta \)): \( \text{Cl}^- < \text{F}^- < \text{H}_2\text{O} < \left[\text{C}_2\text{O}_4\right]^{2-} \).
  • Strong-field ligands (large \( \Delta \)): \( \left[\text{C}_2\text{O}_4\right]^{2-} < \text{CN}^- \).

The correct order is:

\[ \text{Cl}^- < \text{F}^- < \text{H}_2\text{O} < \left[\text{C}_2\text{O}_4\right]^{2-} < \text{CN}^- \]

3. Analyze each option:

  • (E) \( \text{Cl}^- < \text{F}^- < \left[\text{C}_2\text{O}_4\right]^{2-} < \text{H}_2\text{O} < \text{CN}^- \):
    • This is incorrect because \( \text{H}_2\text{O} \) has a smaller splitting than \( \left[\text{C}_2\text{O}_4\right]^{2-} \).
  • (B) \( \text{Cl}^- < \text{F}^- < \text{CN}^- < \text{H}_2\text{O} < \left[\text{C}_2\text{O}_4\right]^{2-} \):
    • This is incorrect because \( \text{CN}^- \) is a strong-field ligand and should come after \( \left[\text{C}_2\text{O}_4\right]^{2-} \).
  • (C) \( \text{F}^- < \text{Cl}^- < \text{CN}^- < \text{H}_2\text{O} < \left[\text{C}_2\text{O}_4\right]^{2-} \):
    • This is incorrect because \( \text{Cl}^- \) is weaker than \( \text{F}^- \), and \( \text{H}_2\text{O} \) comes before \( \left[\text{C}_2\text{O}_4\right]^{2-} \).
  • (D) \( \text{F}^- < \text{Cl}^- < \text{H}_2\text{O} < \text{CN}^- < \left[\text{C}_2\text{O}_4\right]^{2-} \):
    • This is incorrect because \( \text{CN}^- \) is stronger than \( \left[\text{C}_2\text{O}_4\right]^{2-} \).
  • (A) \( \text{Cl}^- < \text{F}^- < \text{H}_2\text{O} < \left[\text{C}_2\text{O}_4\right]^{2-} < \text{CN}^- \):
    • This is correct and matches the spectrochemical series.

4. Final answer:

The correct option is (A).

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Concepts Used:

Chemical Bonding and Molecular Structure

Such a group of atoms is called a molecule. Obviously, there must be some force that holds these constituent atoms together in the molecules. The attractive force which holds various constituents (atoms, ions, etc.) together in different chemical species is called a chemical bond.

Types of Chemical Bonds:

There are 4 types of chemical bonds which are formed by atoms or molecules to yield compounds. 

  • Ionic Bonds - Ionic bonding is a type of chemical bonding which involves a transfer of electrons from one atom or molecule to another.
  • Covalent Bonds - Compounds that contain carbon commonly exhibit this type of chemical bonding. 
  • Hydrogen Bonds -  It is a type of polar covalent bonding between oxygen and hydrogen wherein the hydrogen develops a partial positive charge
  • Polar Bonds - In Polar Covalent chemical bonding, electrons are shared unequally since the more electronegative atom pulls the electron pair closer to itself and away from the less electronegative atom.

Factors Affecting Bond Enthalpy in Chemical Bonding:

  • Size of the Atom
  • Multiplicity of Bonds
  • Number of Lone Pair of Electrons Present
  • Bond Angle