Question:

Which option(s) correctly match(es) the Polymer property with its appropriate Units? 

Show Hint

In polymer science, it’s important to understand the correct units associated with each material property. For example, {toughness} is often expressed in \({J m}^{-3}\), and {flexural strength} in \({Kg m}^{-1} {s}^{-2}\).
Updated On: May 7, 2025
  • P-2; Q-1; R-3; S-4
  • P-2; Q-4; R-3; S-1
  • P-3; Q-1; R-2; S-4
  • P-3; Q-4; R-2; S-1
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is C, D

Solution and Explanation

In this question, we are asked to match the polymer properties with their corresponding units. Let’s analyze each property and match it with the appropriate units.
- Hildebrand solubility parameter (P): This parameter is used to describe the cohesive energy density of a solvent or polymer. It is typically measured in \({MPa}^{1/2}\), which matches with unit (3). Therefore, P-3 is correct.
- Loss modulus (Q): The loss modulus represents the energy lost due to the internal friction in the material under oscillatory stress. Its unit is typically \({Pa}\), which corresponds to unit (1). Hence, Q-1 is correct.
- Toughness (R): Toughness represents the ability of a material to absorb energy and is measured in joules per cubic meter \({J m}^{-3}\). Thus, R-2 is the correct match.
- Flexural strength (S): This property describes the maximum stress a material can withstand in bending. The unit for flexural strength is typically \({Kg m}^{-1} {s}^{-2}\), which matches with unit (4). Therefore, S-4 is correct.
Thus, the correct answers are (C) P-3; Q-1; R-2; S-4 and (D) P-3; Q-4; R-2; S-1.
Was this answer helpful?
0
0

Top Questions on Polymer Science

View More Questions

Questions Asked in GATE XE exam

View More Questions