Step 1: Analyze each set.
(A) and (D): Both rationals and irrationals are dense but have empty interiors, since no interval in \(\mathbb{R}\) consists solely of rationals or irrationals.
(B) The set where \(\sin(a)=1\) is discrete (\(a = \pi/2 + 2n\pi\)), hence no interior.
(C) For \(x^2 + bx + 1 = 0\) to have distinct roots, discriminant \(b^2 - 4>0 \Rightarrow |b|>2.\)
Thus, the set is \((-\infty, -2) \cup (2, \infty)\), which has open intervals ⇒ non-empty interior.
Step 2: Conclusion.
Hence, option (C) is correct.