Which one of the following statements is TRUE with regard to glucose?
- It gives Schiff's test
- It forms addition product with $NaHSO_3$
It does not undergo mutarotation
Its pentaacetate does not react with $NH_2OH$
- B- form of glucose is obtained by crystallisation from conc. solution of glucose
The Correct Option is D
Solution and Explanation
Let’s evaluate each statement about glucose to determine the correct one:
- It gives Schiff's test: False. Glucose does not give a positive Schiff’s test because its aldehyde group is involved in the cyclic hemiacetal form.
- It forms addition product with \( NaHSO_3 \): False. Glucose generally does not form a stable addition product with sodium bisulfite due to its cyclic structure.
- Its pentaacetate does not react with \( NH_2OH \): True. In the pentaacetate form, the carbonyl group of glucose is blocked by acetylation, so it cannot react with hydroxylamine.
- It does not undergo mutarotation: False. Glucose does undergo mutarotation, meaning it interconverts between α and β anomers in aqueous solution.
- β-form of glucose is obtained by crystallisation from concentrated solution of glucose: True. On crystallization from concentrated solution, β-D-glucose is formed.
The true statement related to the given context is:
Its pentaacetate does not react with \( NH_2OH \)
Correct Answer: (D)
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