Question

Which one of the following species will disproportionate in the following reduction potential diagra

• (A) ${Am}^{+3},{Am}^{+4}$
• (B) $Am{o}_2^{+},A{m}^{+3}$
• (C) $Am{O}_2^{+},A{m}^{+4}$
• (D) None of these

Answer 1

The Correct Option is D

Explanation:
The following electrode potential diagram:

We have to find the species which undergoes disproportionation.In general, if the value of emf at the right side of species is greater than that of left side, the species will undergo disproportionation, therefore, will undergo disproportionation reactions.$E_{{Am}^{+}4/{Am}^{+3}}^{\circ }=2.62V$$E_{A{m}^{+2}/A{m}^{+4}}^{\circ }=0.86V$$E_{\text{cell}}^{\circ }=E_{\text{cathode}}^{\circ }-E_{\text{anode}}^{\circ }$$=2.62V-0.86V$$=1.76V$Since,$E^{\circ }$ cell is positive ${Am}^{+4}$ ,${Am}^{3+}$can be converted to $Am{o}_2^{+}$ simultaneously.Hence, the correct option is (D).