The correct answer is Option 1: H3PO2.
To reduce AgNO3 to metallic silver, the oxoacid of phosphorus must have a reducing property. Let's analyze the given options:
H3PO2 (Hypophosphorous acid) has the strongest reducing ability because it contains the highest number of P-H bonds. These P-H bonds can easily donate electrons, making it a good reducing agent. This characteristic allows it to reduce AgNO3 to metallic silver.
Therefore, the oxoacid of phosphorus that can reduce AgNO3 to metallic silver is H3PO2.
The correct answer is Option 1: H3PO2.
Hypophosphorous acid (H3PO2) is a strong reducing agent that can effectively reduce Ag+ ions to Ag, while itself getting oxidized to phosphoric acid (H3PO3) as shown in the following reaction:
\[ 3 \, \text{AgNO}_3 + 4 \, \text{H}_3\text{PO}_2 + \text{H}_2\text{O} \rightarrow 3 \, \text{Ag} + 4 \, \text{H}_3\text{PO}_3 + 3 \, \text{HNO}_3 \]
In this reaction, Hypophosphorous acid reduces silver nitrate (AgNO3) to metallic silver (Ag), while being oxidized to phosphoric acid (H3PO3). The nitric acid (HNO3) is a byproduct of the reaction.
Given below are two statements:
Statement (I): The first ionization energy of Pb is greater than that of Sn.
Statement (II): The first ionization energy of Ge is greater than that of Si.
In light of the above statements, choose the correct answer from the options given below: