Question:

Which one of the following is the most electronegative element configuration?

Updated On: Jun 14, 2022
  • $1 s^{2}, 2 s^{2} 2 p^{6}, 3 s^{2} 3 p^{6}$
  • $1 s^{2}, 2 s^{2} 2 p^{6}, 3 s^{1}$
  • $1 s^{2}, 2 s^{2} 2 p^{6}, 3 s^{2}$
  • $1 s^{2}, 2 s^{2} 2 p^{5}$
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The Correct Option is D

Solution and Explanation

Fluorine is the most electronegative element. Its atomic number is nine and hence its configuration is as $F(9)=1 s^{2}, 2 s^{2}, 2 p^{5}$ Due to its configuration,
it has maximum effective nuclear charge, hence it shows maximum electro negativity.
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Concepts Used:

P-Block Elements

  • P block elements are those in which the last electron enters any of the three p-orbitals of their respective shells. Since a p-subshell has three degenerate p-orbitals each of which can accommodate two electrons, therefore in all there are six groups of p-block elements.
  • P block elements are shiny and usually a good conductor of electricity and heat as they have a tendency to lose an electron. You will find some amazing properties of elements in a P-block element like gallium. It’s a metal that can melt in the palm of your hand. Silicon is also one of the most important metalloids of the p-block group as it is an important component of glass.

P block elements consist of: