Since the boron atom is not surrounded by an octet of electrons, boron halides like BF3 or BCl3 are electron-deficient compounds. They thus have a propensity to operate as potent Lewis acids by taking electrons from several Lewis bases to produce persistent acid-base adducts, serving as catalysts for numerous significant chemical processes.
The bond angle of boron halides, which have a planar structure and a sp2 hybridization, is 120°. The experimentally discovered BX bond lengths, however, are shorter than the values predicted from the halogens' and boron's covalent single bond radii.
In addition to the Lewis acid-base reaction and the most common compounds featuring covalent bonds between a non-metal and a halogen, boron halides are subject to a variety of other reactions. Through hydrolysis processes, these substances react vehemently with water to produce boric acid and hydrogen halide. The broad response below can serve as a representation of this.
Given below are two statements.
In the light of the above statements, choose the correct answer from the options given below:
Given below are two statements:
Statement I: Nitrogen forms oxides with +1 to +5 oxidation states due to the formation of $\mathrm{p} \pi-\mathrm{p} \pi$ bond with oxygen.
Statement II: Nitrogen does not form halides with +5 oxidation state due to the absence of d-orbital in it.
In the light of the above statements, choose the correct answer from the options given below:
Given below are the pairs of group 13 elements showing their relation in terms of atomic radius. $(\mathrm{B}<\mathrm{Al}),(\mathrm{Al}<\mathrm{Ga}),(\mathrm{Ga}<\mathrm{In})$ and $(\mathrm{In}<\mathrm{Tl})$ Identify the elements present in the incorrect pair and in that pair find out the element (X) that has higher ionic radius $\left(\mathrm{M}^{3+}\right)$ than the other one. The atomic number of the element (X) is