Question:

Which one of the following has the same number of atoms as are in 6g of H2O

Updated On: Apr 11, 2025
  • 0.4G He

  • 22g CO2

  • 1g H2

  • 12g CO

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The Correct Option is C

Solution and Explanation

To solve the problem, we need to find which option contains the same number of atoms as 6 g of H2O.

1. Calculate Moles of H2O:
Molar mass of water (H2O) = 18 g/mol
Moles of water = $ \frac{6}{18} = 0.333 \, \text{mol} $

2. Calculate Number of Atoms in H2O:
Each molecule of water contains 3 atoms (2 Hydrogen + 1 Oxygen).
So, total atoms = $0.333 \times 6.022 \times 10^{23} \times 3$
= $6.022 \times 10^{23} \times 1 = 6.022 \times 10^{23}$ atoms

3. Find Which Option Has the Same Number of Atoms:

  • 1 g H2: Molar mass = 2 g/mol
    Moles = $ \frac{1}{2} = 0.5 $ mol
    Each H2 molecule has 2 atoms
    Atoms = $0.5 \times 6.022 \times 10^{23} \times 2 = 6.022 \times 10^{23}$
  • 0.4 g He: Molar mass = 4 g/mol → 0.1 mol → $0.1 \times 6.022 \times 10^{23}$ = fewer atoms
  • 22 g CO2: Molar mass = 44 g/mol → 0.5 mol
    Each CO2 has 3 atoms → $0.5 \times 3 \times 6.022 \times 10^{23}$ = $9.033 \times 10^{23}$ atoms
  • 12 g CO: Molar mass = 28 g/mol → $ \frac{12}{28} \approx 0.43 $ mol
    Each CO has 2 atoms → $0.43 \times 2 \times 6.022 \times 10^{23} \approx 5.2 \times 10^{23}$ atoms

Final Answer:
The option with the same number of atoms as in 6 g of water is 1 g H2.

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Top Questions on Law Of Chemical Equilibrium And Equilibrium Constant

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Concepts Used:

Law of Chemical Equilibrium

Law of Chemical Equilibrium states that at a constant temperature, the rate of a chemical reaction is directly proportional to the product of the molar concentrations of the reactants each raised to a power equal to the corresponding stoichiometric coefficients as represented by the balanced chemical equation.

Let us consider a general reversible reaction;

A+B ↔ C+D

After some time, there is a reduction in reactants A and B and an accumulation of the products C and D. As a result, the rate of the forward reaction decreases and that of backward reaction increases. 

Eventually, the two reactions occur at the same rate and a state of equilibrium is attained. 

By applying the Law of Mass Action;

The rate of forward reaction;

Rf = Kf [A]a [B]b

The rate of backward reaction;

Rb = Kb [C]c [D]d

Where,

[A], [B], [C] and [D] are the concentrations of A, B, C and D at equilibrium respectively.

a, b, c, and d are the stoichiometric coefficients of A, B, C and D respectively.

Kf and Kb­ are the rate constants of forward and backward reactions.

However, at equilibrium,

Rate of forward reaction = Rate of backward reaction.

Kc is called the equilibrium constant expressed in terms of molar concentrations.

The above equation is known as the equation of Law of Chemical Equilibrium.