Which one of the following compound hydrocarbons can show isomerism?
- C2H4
- C2H6
- C3H8
- C4H10
The Correct Option is D
Solution and Explanation
Isomerism occurs when compounds have the same molecular formula but different structural arrangements. Among the given options:
- \( \text{C}_2\text{H}_4 \): Ethene, a simple alkene with no possibility of isomerism.
- \( \text{C}_2\text{H}_6 \): Ethane, a simple alkane with no possibility of isomerism.
- \( \text{C}_2\text{H}_8 \): Not a valid hydrocarbon formula (violates the general formula \( \text{C}_n\text{H}_{2n+2} \)).
- \( \text{C}_4\text{H}_{10} \): Butane, which can exhibit structural isomerism (e.g., n-butane and isobutane).
Final Answer: The compound that can show isomerism is \( \mathbf{\text{C}_4\text{H}_{10}} \), which corresponds to option \( \mathbf{(4)} \).
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