Question:

Which one is incorrect with regard to pK$_a$?

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  • \(K_a\): Acid dissociation constant. Larger \(K_a \implies\) stronger acid.
  • pK\(_a = -\log_{10}K_a\). Smaller pK\(_a \implies\) stronger acid.
  • pH = \(-\log_{10}[\text{H}^+]\). Measures hydrogen ion concentration (acidity/basicity of a solution).
  • Henderson-Hasselbalch equation relates pH, pK\(_a\), and the ratio of conjugate base to acid: pH = pK\(_a\) + \(\log_{10}(\frac{[\text{A}^-]}{[\text{HA}]})\).
Updated On: Jun 12, 2025
  • In pK\(_a\), K\(_a\) is acid dissociation constant
  • pK\(_a\) is measurement of the concentration of hydrogen ions in a solution
  • Higher the K\(_a\) the stronger the acid
  • pK\(_a\) is used to show the strength of an acid
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The Correct Option is B

Solution and Explanation

The given question requires identifying which statement regarding pKa is incorrect. To solve this, we must analyze the provided statements:

Statement Analysis:

  • In pKa, Ka is acid dissociation constant: This statement is correct. Ka represents the acid dissociation constant for a given acid.

  • pKa is measurement of the concentration of hydrogen ions in a solution: This statement is incorrect. pKa is not a direct measurement of hydrogen ion concentration. It is a logarithmic scale that measures the strength of an acid by expressing the acid dissociation constant.

  • Higher the Ka the stronger the acid: This statement is correct. A higher Ka indicates greater dissociation into ions, thus a stronger acid.

  • pKa is used to show the strength of an acid: This statement is correct. pKa provides a measure of the acid's strength; lower pKa means a stronger acid as it dissociates more completely.

Therefore, the incorrect statement among the options is: pKa is measurement of the concentration of hydrogen ions in a solution.
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