Question:
Which one amongst the following pairs of ions cannot be separated by $H_2 S$ in dilute HCl ?
Which one amongst the following pairs of ions cannot be separated by $H_2 S$ in dilute HCl ?
Updated On: Sep 1, 2023
- $Bi^{3+} , Sn^{4+}$
- $Al^{3+} , Hg^{2+}$
- $Zn^{2+} , Cu^{2+}$
- $Ni^{2+} , Cu^{2+}$
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The Correct Option is A
Solution and Explanation
The correct answer is A:\(Bi^{3+},Sn^{4+}\)
Both \(Bi^{3+}\) and \(Sn^{4+}\) belongs to same analytical group II.They cannot be seperated by \(H_2S\) in dilute \(HCL\).
Both \(Bi^{3+}\) and \(Sn^{4+}\) belongs to same analytical group II.They cannot be seperated by \(H_2S\) in dilute \(HCL\).
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