Question

Which one among the following structures is the most stable conformer of (Z)-pent-2-ene?

• A.
• B.
• C.
• D.

Hint:

For determining the stability of conformers, consider steric hindrance and electronic effects. Z-configuration indicates cis-arrangement of substituents, which can influence stability based on the size and interactions of substituents.

Answer 1

The Correct Option is C

Step 1: Definition of (Z)-pent-2-ene. The structure of (Z)-pent-2-ene corresponds to a pentene molecule with a double bond at the second carbon, where the substituents on either side of the double bond are arranged in the emph{cis} configuration (Z-configuration). The stability of the conformer depends on minimizing steric hindrance and repulsion between substituents.
Step 2: Analyze the given options. 
- Option (A): This structure has a significant steric hindrance due to the placement of bulky substituents. 
- Option (B): Similar steric hindrance as in Option (A). 
- Option (C): The substituents are arranged in a way that minimizes steric hindrance and is more stable. 
- Option (D): Incorrect as it does not conform to the Z-configuration.
Step 3: Conclusion. Option (C) represents the most stable conformer of (Z)-pent-2-ene because it minimizes steric hindrance and is in the Z-configuration.