Which of the Phosphorus oxoacid can create silver mirror from $AgNO _3$ solution?
- $H _4 P _2 O _7$
- $\left( HPO _3\right)_n$
- $H _4 P _2 O _6$
- $H _4 P _2 O _5$
The Correct Option is D
Solution and Explanation
Phosphorus oxoacids with a \( \text{P-H} \) bond act as reducing agents and can reduce \( \text{AgNO}_3 \) to silver (\( \text{Ag} \)), producing a silver mirror.
Among the given options, \( \text{H}_4\text{P}_2\text{O}_5 \) contains a \( \text{P-H} \) bond, which makes it capable of reducing \( \text{AgNO}_3 \).
The reaction mechanism involves the oxidation of the oxoacid, with the \( \text{P-H} \) bond breaking and silver (\( \text{Ag} \)) being reduced.
The silver forms a mirror on the surface of the reaction vessel.
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Concepts Used:
Balancing a redox reaction
The method that is based on the difference in oxidation number of oxidizing agent and the reducing agent is known as oxidation number. The half-reaction method entirely depends on the division of the redox reactions into oxidation half and reduction half. It entirely depends on the individual which method to choose and use.
Oxidation Number Method:
Like various other reactions, it is very important to write the correct compositions and formulas. A very important thing to keep in mind while writing oxidation-reduction reactions is to write the compositions and formulas of the substances and the products present in the chemical reaction in a very correct manner.
Half-Reaction Method:
In this procedure, we decouple the equation into two halves. After that, we balance both the parts of the reaction separately. Finally, we add them together to get a balanced equation.