Question

Which of the following statements is \emph{correct regarding the coordination compound \([Fe(CN)_6]^{4-}\) and fructose structure?}

• A. The EAN of iron in \([Fe(CN)_6]^{4-}\) is 36 and fructose forms a pyranose ring.
• B. The EAN of iron in \([Fe(CN)_6]^{4-}\) is 36 and fructose forms a furanose ring.
• C. The compound exhibits ionisation isomerism and fructose is a non-reducing sugar.
• D. The EAN of Fe is 30 and fructose forms a pyranose ring.

Hint:

EAN = Atomic number - Oxidation state + 2 × (number of ligands). Fructose, being a ketose, cyclizes to form a five-membered furanose ring.

Answer 1

The Correct Option is B

In \([Fe(CN)_6]^{4-}\): - Oxidation state of Fe is +2 (since CN⁻ is -1 each × 6 = -6; overall charge = -4). - Atomic number of Fe = 26 - EAN = \( 26 - 2 + 6 \times 2 = 36 \) Fructose is a ketose and forms a furanose ring via hemiketal formation. Hence, statement (2) is correct.